post - Debug small code - receiving error -

post - Debug small code - receiving error -

January 15, 2012

कोड चलाने पर मुझे त्रुटि प्राप्त हो रही है:

  ubuntu @ubuntu-VirtualBox: ~ $ Curl -X POST http: // localhost: 5984 / books / _temp_view? Group = true -H "सामग्री-प्रकार: आवेदन / जेसन" -d '{    "मैप": "फ़ंक्शन (डॉक्टर) {if (doc.formats) {for (var i में doc.formats) {emit (doc.formats [i]);}}}", "कम करें": "_count"} ' {"error": "bad_request", "reason": "invalid_json"}  उबुंटू @ उबुन्टू-वर्चुअलबॉक्स: ~ $    
 
  आपको संभवतः शेल में अंतर या उद्धरणों के साथ समस्या हो रही है। अपने JSON को एक फ़ाइल में सहेजने का प्रयास करें, फिर उस फ़ाइल नाम को कमांड लाइन पर JSON लिखने के बजाय कर्ल को पास करें।  
 उदाहरण /tmp/ex.json में अपना JSON जीवन मानते हुए उदाहरण:  < प्री>  कर्ल -XPOST -Hcontent-type: application / json -d@/tmp/ex.json http: // localhost: 5984 / books / _temp_view? Group = true


















Get link





Facebook





X





Pinterest





Email





Other Apps




Comments





Post a Comment







Popular Posts




Xml parsing with python -



    I am using  xml  with Python  xmltodict . But I'm getting the following error,    xml.parsers.expat.ExpatError: mismatched tag: line 2890, column2    this is my code,    import xmltodict import urllib2 url = "url here" data = xmltodict.parse (urllib2.urlopen (url) .read () print data    I have tried to use the  Entry    here, with the at print, the print code 'urlib2 import lxml.etree',    Url = "Url here" xmldata = urllib2.urlopen (url) .read () root = ET.frost string (xmldata) print 'full' print route    This also helps me Error,    lxml.etree.XMLSyntaxError: Opening and closing tag mismatch: Client ID line 54 and type, line 55, column 14    I know that there is a problem in  XML   My question is, what is the way to read all the nodes except that it is  xml ?      






c# - WPF UserControl.Loaded event does not trigger -



    my program when I (mouseenter event) a TransportOrderLineDetailView to hover over a certain UserControl (Here I use TransportOrderLineUserControl) Should be shown.   The TransportOrderLineDetailView should be placed at the bottom right of my screen. For this I want to see the actual Wide & amp; The actual highlight for the actual placement is because those 2 properties require a different value than 0, because I execute this code with the DetailView.Loaded event.   I use the exact same type for two other items I do not work for TransportOrderLineDetailView   Code where the scene is generated:.    TransportOrderLineDetailView tolDetailView = new TransportOrderLineDetailView (New TransportOrderLineDetailViewModel (transportOrderLine)); Window.DetailContent = tolView; TolView.Loaded + = SetDetailViewOnUI;    code-behind view:    public TransportOrderLineDetailView (TransportOrderLineDetailViewModel detailViewModel) {InitializeComponent (); Datacontex = descriptionviewmodel; }    M...











ios - Pixel position of UIImageView in coordinate system -



    I am stuck in an interesting situation where I have 1.4, 1.4 x for reset, y is a pixel dot Start by putting imageview .. and why .. any document link?   Please any light please.   Thank you.       View = [[UIView alloc] initWithFrame: CGRectMake (10, 50, 20, 20)]; View.backgroundColor = [UIColor greenColor]; [Self.view addSubview: view]; Scene 2 = [[UIView alloc] initWithFrame: CGRectMake (10.4, 70, 20, 20)]; View2.backgroundColor = [UIColor redColor]; [Self.view addSubview: view2]; Scene 3 = [[UIView alloc] initWithFrame: CGRectMake (11, 90, 20, 20)]; View3.backgroundColor = [UIColor blue color]; [Self.view addSubview: view3];    The first is a visual reference, I know that its original x is at 20px.   Be careful here, due to retina @ 2x resolution 10 points x = 20 px, and 11 points x = 22 px. You speak in the code in the code, and give a pixel result on the screen.   I tried to change the X coordinate gradually here I found:     9.75 & lt; X & lt; = 10.25: Red square star...








Powered by Blogger