I am using jQuery 1.6.2 and jQuery-UI 1.9.0. I have some tabs like this:
& lt; Li & gt; & Lt; A href = "#document-tab" onclick = "return document tabgate ('CRFilingDocument.do', null);> Document & lt; / a & gt; & lt; / li & gt; & lt; li & Gt; & lt; a href = "#tigant-tab" onclick = "Return Claimant Tabgate ('Crifling Lightning Dictate.', 'Empty)" & gt; Litigents & lt; / a & gt; & lt; / li & Gt; & lt; li & gt; & lt; a href = "# scheduling-tab" onclic = "return scheduling tabgate ('CRFiling sd alk.do', blank);" gt; scheduling & lt; / a & gt; ;
I have an active function before setup
jQuery ("# reviewtabs"). Tab ({select: function (event, UI) {returnSomething};}, show: function (event, UI) {// some stuff}, activate first: function Event, UI) {returnSomething ();}});
Presenting one of those tabs on JSP, I first want to check hidden HTML input in activate. In the Chrome console I can see from the HTML typing ui.oldPanel, how can the value of the hidden field be obtained? I have tried ui.oldPanel.find ("dirty check"). Price and it is mandatory to come back.
thanks
OK, if Ui.oldPanel
is not undefined, we should know what is dirty check
is it an input id? Input CSS class? or something else?
If Dirty Investigation
ID
ui.oldPanel.find ('# dirty check'). Val ();
If the dirty check
is its CSS class, then use another method:
ui.oldPanel.find ( '.dirtyCheck') .val ();
If the return value is still compulsory, then double check that your input is actually in ui.oldPanel
and give us the html where input is.
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