I am new to php. I have downloaded xampp and 2 column id (primary key, auto-increment), army (INT value)
In my index.php I only have one input text and a submit button:
And this is my submit script:
$ sql = "Enter the update (cena) values ('$ _POST [cena]') ) "; Mysqli_query ($ conn, $ sql); Mysqli_query ($ mysqli_query ($ con));} "1 record added" echo; mysqli_close ($ thief);
< P> When I enter a value in the text input, and the submit button is pressed on the whites: "1 record added" but when I look in my database in phpMyAdmin, I get 2 records. Example:
I enter 123 in text input
I see phpMyAdmin:
+ ---- + ----- - + | ID | Army | + ---- + ------ + | 1 | 123 | 2 | 123 | + ---- + ------ +
I Why not use any loops?
thanks
This is because you use the mysqli_query
twice:
mysqli_query ($ con, $ sql)
then , when you insert data, and when you
$ sql = "update (sew) include values ( '$ _POST [cena]')"; If (! Mysqli_query ($ con, $ sql) () die ( "Error: '. Mysqli_error ($ con));}
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