awk - grepping/awking to remove entire line that contains a specific character -


I have a grep (possibly awk?) Question that I have the following data (2 colon, different from tab) 

  a._testudineus anm a_battery art a_capella_singing act | Psy a_cappella_singing act | Psy

i For example, the results I want are: 

  a._testudineus anm a_battery art

Is there a quick / efficient grep / awk that can help me with this? The data is too large (approximately 5 GB).

Thanks in advance.

grep is the device: 

  $ Grep -v "|" File

You can also use awk , of course: 

  $ awk '! / / | / 'File a. _STASTININAZA AM A_BATTERY ART

I go to grep because this device is specially designed for such things: man Grep is called print line matching a pattern .

In fact, we copy the file 1000 times and compare the execution time: 

  $ wc file 4404 8808 101292 file  
  $ time grep -v "|" Real 0m0.031s user 0m0.000s sys 0m0.012s $ Open file '! / \ | / 'File real 0m0.030s user 0m0.005s sys 0m0.010s  
 
 and 10000 file real lines also: 
 
  $ wc file 44404 88808 1021292 File $ time grep -v "|" Real 0m0.300s user 0m0.028s sys 0m0.068s $ time awk '! / \ | / 'File true 0m0.314s user 0m0.009s sys 0m0.063s

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